overall accuracy: 84.1% accuracy last 50: 86% record: 43 score: 43 ∫(csc x cot x)dx = sec x + c csc x + c…

overall accuracy: 84.1% accuracy last 50: 86% record: 43 score: 43 ∫(csc x cot x)dx = sec x + c csc x + c - sec x + c - csc x + c high score board: overall refresh you must have at least 100 to be on the board. # name record answer submitting is not possible on this problem. just follow the instructions above.

overall accuracy: 84.1% accuracy last 50: 86% record: 43 score: 43 ∫(csc x cot x)dx = sec x + c csc x + c - sec x + c - csc x + c high score board: overall refresh you must have at least 100 to be on the board. # name record answer submitting is not possible on this problem. just follow the instructions above.

Answer

Explanation:

Step1: Recall derivative formula

We know that the derivative of $-\csc x$ with respect to $x$ is $\csc x\cot x$, i.e., $\frac{d}{dx}(-\csc x)=\csc x\cot x$.

Step2: Use integral - derivative relationship

By the fundamental theorem of calculus, if $F'(x) = f(x)$, then $\int f(x)dx=F(x)+C$. Since $\frac{d}{dx}(-\csc x)=\csc x\cot x$, we have $\int(\csc x\cot x)dx =-\csc x + C$.

Answer:

D. $-\csc x + C$