part 10 of 10\nsummarize the pertinent information obtained by applying the graphing strategy and sketch the…

part 10 of 10\nsummarize the pertinent information obtained by applying the graphing strategy and sketch the graph of f(x)=6xe^(-0.5x).\nwhich graph below shows f(x)?\na.\nb.\nc.\nd.

part 10 of 10\nsummarize the pertinent information obtained by applying the graphing strategy and sketch the graph of f(x)=6xe^(-0.5x).\nwhich graph below shows f(x)?\na.\nb.\nc.\nd.

Answer

Explanation:

Step1: Find the derivative of (f(x))

Use the product - rule ((uv)^\prime = u^\prime v+uv^\prime), where (u = 6x) and (v=e^{-0.5x}). (u^\prime=6) and (v^\prime=- 0.5e^{-0.5x}). Then (f^\prime(x)=6e^{-0.5x}-3xe^{-0.5x}=e^{-0.5x}(6 - 3x)).

Step2: Find the critical points

Set (f^\prime(x)=0). Since (e^{-0.5x}\gt0) for all real (x), we solve (6 - 3x = 0), which gives (x = 2).

Step3: Analyze the sign of the derivative

When (x\lt2), (f^\prime(x)=e^{-0.5x}(6 - 3x)\gt0), so (f(x)) is increasing. When (x\gt2), (f^\prime(x)=e^{-0.5x}(6 - 3x)\lt0), so (f(x)) is decreasing. So (x = 2) is a local maximum.

Step4: Find the (y) - value at the local maximum

(f(2)=6\times2\times e^{-0.5\times2}=12e^{-1}\approx4.42).

Step5: Analyze the end - behavior

As (x\to-\infty), (6x\to-\infty) and (e^{-0.5x}\to\infty), so (y = f(x)\to-\infty). As (x\to\infty), the exponential decay (e^{-0.5x}) dominates, and (y = f(x)\to0).

Answer:

D