a particle that moves along a straight line has velocity $v(t) = t^2 e^{-2t}$ meters per second after $t$…

a particle that moves along a straight line has velocity $v(t) = t^2 e^{-2t}$ meters per second after $t$ seconds. how many meters will it travel during the first $t$ seconds (from time=0 to time=t)?

a particle that moves along a straight line has velocity $v(t) = t^2 e^{-2t}$ meters per second after $t$ seconds. how many meters will it travel during the first $t$ seconds (from time=0 to time=t)?

Answer

Answer:

$-\frac{1}{2}t^{2}e^{-2t} - \frac{1}{2}te^{-2t} - \frac{1}{4}e^{-2t} + \frac{1}{4}$