partner problem #9\nfind the slope of tangent line to curve (f(x)= - 2x^{3}+4x^{2}+3)
partner problem #9\nfind the slope of tangent line to curve (f(x)= - 2x^{3}+4x^{2}+3)
Answer
Explanation:
Step1: Differentiate the function
The derivative of $y = - 2x^{3}+4x^{2}+3$ using the power - rule $\frac{d}{dx}(x^{n})=nx^{n - 1}$ is $y^\prime=-6x^{2}+8x$. The derivative of a function at a point gives the slope of the tangent line to the curve of the function at that point. Since no specific point is given, the general formula for the slope of the tangent line is the derivative of the function.
Answer:
The slope of the tangent line is $m=-6x^{2}+8x$