what is the period of y = csc(x)?\nπ\n2π\n3π\n4π

Answer:

B. $2\pi$

Explanation:

Step1: Recall csc - sine relationship

$\csc(x)=\frac{1}{\sin(x)}$

Step2: Know sine function period

The period of $y = \sin(x)$ is $2\pi$.

Step3: Determine csc period

Since $\csc(x)$ is the reciprocal of $\sin(x)$, and the zero - points of $\sin(x)$ (where $\csc(x)$ is undefined) repeat every $2\pi$, the period of $y=\csc(x)$ is also $2\pi$.