what is the period of the secant function?\n$\frac{pi}{2}$\n$pi$\n$2pi$\n$4pi$\ndone

what is the period of the secant function?\n$\frac{pi}{2}$\n$pi$\n$2pi$\n$4pi$\ndone
Answer
Explanation:
Step1: Recall secant - cosine relation
The secant function is defined as $y = \sec(x)=\frac{1}{\cos(x)}$.
Step2: Recall cosine function period
The period of the cosine function $y = \cos(x)$ is $2\pi$.
Step3: Determine secant function period
Since $\sec(x)=\frac{1}{\cos(x)}$, and the values of $\cos(x)$ repeat every $2\pi$, the values of $\sec(x)$ also repeat every $2\pi$. So the period of $y=\sec(x)$ is $2\pi$.
Answer:
C. $2\pi$