what is the period of the secant function?\n$\frac{pi}{2}$\n$pi$\n$2pi$\n$4pi$\ndone

what is the period of the secant function?\n$\frac{pi}{2}$\n$pi$\n$2pi$\n$4pi$\ndone

what is the period of the secant function?\n$\frac{pi}{2}$\n$pi$\n$2pi$\n$4pi$\ndone

Answer

Explanation:

Step1: Recall secant - cosine relation

The secant function is defined as $y = \sec(x)=\frac{1}{\cos(x)}$.

Step2: Recall cosine function period

The period of the cosine function $y = \cos(x)$ is $2\pi$.

Step3: Determine secant function period

Since $\sec(x)=\frac{1}{\cos(x)}$, and the values of $\cos(x)$ repeat every $2\pi$, the values of $\sec(x)$ also repeat every $2\pi$. So the period of $y=\sec(x)$ is $2\pi$.

Answer:

C. $2\pi$