what is the period of y = sin(3x)?\n\\(\\frac{\\pi}{3})\\n\\(\\frac{2\\pi}{3})\\n3\\pi\\n6\\pi

Answer:

B. $\frac{2\pi}{3}$

Explanation:

Step1: Recall the period - formula for sine function

The general form of a sine function is $y = A\sin(Bx - C)+D$, and its period $T$ is given by the formula $T=\frac{2\pi}{|B|}$.

Step2: Identify the value of B

For the function $y = \sin(3x)$, we have $B = 3$.

Step3: Calculate the period

Substitute $B = 3$ into the period - formula $T=\frac{2\pi}{|B|}$. Since $|3| = 3$, then $T=\frac{2\pi}{3}$.