2. -/8 points details my notes ask your teacher this question has several parts that must be completed…

2. -/8 points details my notes ask your teacher this question has several parts that must be completed sequentially. if you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. tutorial exercise find an equation of the tangent line to the curve at the point (2, 0). y = ln(x³ - 7) part 1 of 5 recall that to find the equation of a line with slope m through a point (x₀, y₀), we can use y - y₀ = m(x - x₀). for y = f(x), the slope of the tangent line at (x₀, y₀) is given by m = f (x₀). note that y = ln(x³ - 7) is a composition, and so we must use the chain rule d/dxf(g(x)) = f (g(x))g(x) to find its derivative. the “inside” function is x³ - 7 and the “outside” function is
Answer
Explanation:
Step1: Identify outer - function
For a composite function $y = \ln(u)$ where $u=x^{3}-7$, the outside function is $\ln(u)$.
Answer:
$\ln(u)$