0.3/0.5 points details my notes note: type pi for π if needed. enter dne as an answer if a particular…

0.3/0.5 points details my notes note: type pi for π if needed. enter dne as an answer if a particular transformation does not app suppose f(t)=sec(2t + π/4). the period of f is π the graph of f is obtained by neither stretching nor shrinking the graph of y = sec t by a factor of and then shifting the graph units to the left. draw the graph of f. see the instructions above for when the graphs from this assignment are du
Answer
Explanation:
Step1: Recall secant - function transformation formula
The general form of a secant - function is $y = A\sec(Bt - C)+D$. For the function $f(t)=\sec(2t+\frac{\pi}{4})$, we can rewrite it as $f(t)=\sec(2(t + \frac{\pi}{8}))$. Here $A = 1$, $B = 2$, $C=-\frac{\pi}{4}$, and $D = 0$.
Step2: Determine the horizontal stretch/shrink factor
The horizontal stretch/shrink factor of the graph of $y=\sec t$ to get $y = \sec(Bt)$ is given by $\frac{1}{|B|}$. Since $B = 2$, the graph of $y=\sec t$ is shrunk horizontally by a factor of $\frac{1}{2}$.
Step3: Determine the horizontal shift
For the function $y=\sec(B(t - h))$, the horizontal shift is $h$. For $f(t)=\sec(2(t+\frac{\pi}{8}))$, the shift is $\frac{\pi}{8}$ units to the left.
Answer:
The graph of $f$ is obtained by shrinking the graph of $y = \sec t$ by a factor of $\frac{1}{2}$ and then shifting the graph $\frac{\pi}{8}$ units to the left.