-/1 points details my notes tanapcalc10 4.2.052.mi. find the inflection point, if it exists, of the…

-/1 points details my notes tanapcalc10 4.2.052.mi. find the inflection point, if it exists, of the function. (if an answer does not exist, enter dne.) g(x) = 4x^3 - 6x^2 + 6x - 5 (x, y) = ( ) need help? read it master it
Answer
Explanation:
Step1: Find the first - derivative
Using the power rule $(x^n)'=nx^{n - 1}$, for $g(x)=4x^{3}-6x^{2}+6x - 5$, we have $g'(x)=12x^{2}-12x + 6$.
Step2: Find the second - derivative
Differentiate $g'(x)$ again. $g''(x)=24x-12$.
Step3: Set the second - derivative equal to zero
Set $g''(x) = 0$, so $24x-12 = 0$. Solving for $x$ gives $24x=12$, then $x=\frac{1}{2}$.
Step4: Find the $y$ - coordinate
Substitute $x = \frac{1}{2}$ into the original function $g(x)$. $g(\frac{1}{2})=4(\frac{1}{2})^{3}-6(\frac{1}{2})^{2}+6(\frac{1}{2})-5=4\times\frac{1}{8}-6\times\frac{1}{4}+3 - 5=\frac{1}{2}-\frac{3}{2}+3 - 5=-3$.
Answer:
$(\frac{1}{2},-3)$