at which points is the function continuous?\ny = \\sqrt4{2x - 5}\nthe function is continuous on .\n(simplify…

at which points is the function continuous?\ny = \\sqrt4{2x - 5}\nthe function is continuous on .\n(simplify your answer. type your answer in interval notation. use integers or fractions for any numbers in the expression.)

at which points is the function continuous?\ny = \\sqrt4{2x - 5}\nthe function is continuous on .\n(simplify your answer. type your answer in interval notation. use integers or fractions for any numbers in the expression.)

Answer

Explanation:

Step1: Recall domain of fourth - root function

For $y = \sqrt[4]{u}$, $u\geq0$. Here $u = 2x - 5$.

Step2: Set up inequality

We set $2x-5\geq0$.

Step3: Solve the inequality

Add 5 to both sides: $2x\geq5$. Then divide by 2: $x\geq\frac{5}{2}$.

Answer:

$[\frac{5}{2},\infty)$