precalculus quiz 4\n1. determine the features of the following function, then graph at least one period of…

precalculus quiz 4\n1. determine the features of the following function, then graph at least one period of the function, including asymptotes.\nf(x)=2tan(2(x - π/4)) + 1\nvertical stretch\nperiod\nphase shift\nvertical translation\nequation of all asymptotes

precalculus quiz 4\n1. determine the features of the following function, then graph at least one period of the function, including asymptotes.\nf(x)=2tan(2(x - π/4)) + 1\nvertical stretch\nperiod\nphase shift\nvertical translation\nequation of all asymptotes

Answer

Explanation:

Step1: Identify vertical stretch

The coefficient of the tangent function gives the vertical stretch. For $y = 2\tan(2(x-\frac{\pi}{4}))+1$, the vertical - stretch is 2.

Step2: Find the period

The period of the tangent function $y = A\tan(Bx - C)+D$ is given by $\frac{\pi}{|B|}$. Here $B = 2$, so the period is $\frac{\pi}{2}$.

Step3: Determine phase shift

The phase - shift of the function $y = A\tan(Bx - C)+D$ is $\frac{C}{B}$. Here $C=\frac{\pi}{2}$ (since $Bx - C=2x-\frac{\pi}{2}$) and $B = 2$, so the phase shift is $\frac{\pi}{4}$ to the right.

Step4: Find vertical translation

The value of $D$ gives the vertical translation. For $y = 2\tan(2(x-\frac{\pi}{4}))+1$, the vertical translation is 1 unit up.

Step5: Find equations of asymptotes

The asymptotes of the tangent function $y=\tan x$ occur at $x = \frac{\pi}{2}+k\pi,k\in\mathbb{Z}$. For $y = 2\tan(2(x-\frac{\pi}{4}))+1$, we set $2(x-\frac{\pi}{4})=\frac{\pi}{2}+k\pi$. Solving for $x$: [ \begin{align*} 2(x-\frac{\pi}{4})&=\frac{\pi}{2}+k\pi\ 2x-\frac{\pi}{2}&=\frac{\pi}{2}+k\pi\ 2x&=\pi + k\pi\ x&=\frac{\pi}{2}(k + 1),k\in\mathbb{Z} \end{align*} ]

Answer:

Feature Value
Vertical stretch 2
Period $\frac{\pi}{2}$
Phase shift $\frac{\pi}{4}$ to the right
Vertical translation 1 unit up
Equation of all asymptotes $x=\frac{\pi}{2}(k + 1),k\in\mathbb{Z}$