precalculus quiz 4\n1. determine the features of the following function, then graph at least one period of…

precalculus quiz 4\n1. determine the features of the following function, then graph at least one period of the function, including asymptotes.\nf(x)=2tan(2(x - π/4)) + 1\nvertical stretch\nperiod\nphase shift\nvertical translation\nequation of all asymptotes
Answer
Explanation:
Step1: Identify vertical stretch
The coefficient of the tangent function gives the vertical stretch. For $y = 2\tan(2(x-\frac{\pi}{4}))+1$, the vertical - stretch is 2.
Step2: Find the period
The period of the tangent function $y = A\tan(Bx - C)+D$ is given by $\frac{\pi}{|B|}$. Here $B = 2$, so the period is $\frac{\pi}{2}$.
Step3: Determine phase shift
The phase - shift of the function $y = A\tan(Bx - C)+D$ is $\frac{C}{B}$. Here $C=\frac{\pi}{2}$ (since $Bx - C=2x-\frac{\pi}{2}$) and $B = 2$, so the phase shift is $\frac{\pi}{4}$ to the right.
Step4: Find vertical translation
The value of $D$ gives the vertical translation. For $y = 2\tan(2(x-\frac{\pi}{4}))+1$, the vertical translation is 1 unit up.
Step5: Find equations of asymptotes
The asymptotes of the tangent function $y=\tan x$ occur at $x = \frac{\pi}{2}+k\pi,k\in\mathbb{Z}$. For $y = 2\tan(2(x-\frac{\pi}{4}))+1$, we set $2(x-\frac{\pi}{4})=\frac{\pi}{2}+k\pi$. Solving for $x$: [ \begin{align*} 2(x-\frac{\pi}{4})&=\frac{\pi}{2}+k\pi\ 2x-\frac{\pi}{2}&=\frac{\pi}{2}+k\pi\ 2x&=\pi + k\pi\ x&=\frac{\pi}{2}(k + 1),k\in\mathbb{Z} \end{align*} ]
Answer:
| Feature | Value |
|---|---|
| Vertical stretch | 2 |
| Period | $\frac{\pi}{2}$ |
| Phase shift | $\frac{\pi}{4}$ to the right |
| Vertical translation | 1 unit up |
| Equation of all asymptotes | $x=\frac{\pi}{2}(k + 1),k\in\mathbb{Z}$ |