provide an appropriate response. is the function given by f(x) = √(x - 1) continuous at x = -2? why or why…
provide an appropriate response. is the function given by f(x) = √(x - 1) continuous at x = -2? why or why not? edit view insert format tools table 12pt paragraph b i u a t²
Answer
Explanation:
Step1: Check domain of the function
For $y = \sqrt{x - 1}$, the expression under the square - root must be non - negative, i.e., $x-1\geq0$, so $x\geq1$.
Step2: Analyze the point $x = - 2$
The value $x=-2$ is not in the domain of the function $f(x)=\sqrt{x - 1}$.
Answer:
The function $f(x)=\sqrt{x - 1}$ is not continuous at $x = - 2$ because $x=-2$ is not in the domain of the function.