in which quadrant(s) are tan(x) and sin(x) both negative?\nquadrant ii\nquadrants ii and iii\nquadrant…

in which quadrant(s) are tan(x) and sin(x) both negative?\nquadrant ii\nquadrants ii and iii\nquadrant iv\nquadrants iii and iv
Answer
Explanation:
Step1: Recall sine - tangent signs in quadrants
Recall the signs of trigonometric functions in each quadrant. $\sin(x)=\frac{y}{r}$ and $\tan(x)=\frac{y}{x}$ where $(x,y)$ is a point on the terminal side of the angle $x$ and $r = \sqrt{x^{2}+y^{2}}>0$.
Step2: Analyze quadrant for negative sine
In quadrant I: $x>0,y>0$, so $\sin(x)=\frac{y}{r}>0$; in quadrant II: $x < 0,y>0$, so $\sin(x)=\frac{y}{r}>0$; in quadrant III: $x<0,y < 0$, so $\sin(x)=\frac{y}{r}<0$; in quadrant IV: $x>0,y < 0$, so $\sin(x)=\frac{y}{r}<0$.
Step3: Analyze quadrant for negative tangent
In quadrant I: $x>0,y>0$, so $\tan(x)=\frac{y}{x}>0$; in quadrant II: $x < 0,y>0$, so $\tan(x)=\frac{y}{x}<0$; in quadrant III: $x<0,y < 0$, so $\tan(x)=\frac{y}{x}>0$; in quadrant IV: $x>0,y < 0$, so $\tan(x)=\frac{y}{x}<0$.
Step4: Find common quadrants
We want the quadrants where both $\sin(x)<0$ and $\tan(x)<0$. From the above - analysis, the common quadrant is quadrant IV.
Answer:
C. quadrant IV