in which quadrant(s) are tan(x) and sin(x) both negative?\nquadrant ii\nquadrants ii and iii\nquadrant…

in which quadrant(s) are tan(x) and sin(x) both negative?\nquadrant ii\nquadrants ii and iii\nquadrant iv\nquadrants iii and iv

in which quadrant(s) are tan(x) and sin(x) both negative?\nquadrant ii\nquadrants ii and iii\nquadrant iv\nquadrants iii and iv

Answer

Explanation:

Step1: Recall sine - tangent signs in quadrants

Recall the signs of trigonometric functions in each quadrant. $\sin(x)=\frac{y}{r}$ and $\tan(x)=\frac{y}{x}$ where $(x,y)$ is a point on the terminal side of the angle $x$ and $r = \sqrt{x^{2}+y^{2}}>0$.

Step2: Analyze quadrant for negative sine

In quadrant I: $x>0,y>0$, so $\sin(x)=\frac{y}{r}>0$; in quadrant II: $x < 0,y>0$, so $\sin(x)=\frac{y}{r}>0$; in quadrant III: $x<0,y < 0$, so $\sin(x)=\frac{y}{r}<0$; in quadrant IV: $x>0,y < 0$, so $\sin(x)=\frac{y}{r}<0$.

Step3: Analyze quadrant for negative tangent

In quadrant I: $x>0,y>0$, so $\tan(x)=\frac{y}{x}>0$; in quadrant II: $x < 0,y>0$, so $\tan(x)=\frac{y}{x}<0$; in quadrant III: $x<0,y < 0$, so $\tan(x)=\frac{y}{x}>0$; in quadrant IV: $x>0,y < 0$, so $\tan(x)=\frac{y}{x}<0$.

Step4: Find common quadrants

We want the quadrants where both $\sin(x)<0$ and $\tan(x)<0$. From the above - analysis, the common quadrant is quadrant IV.

Answer:

C. quadrant IV