question 8 of 10 if f(3) = 191.5 when r = 0.03 for the function f(t)=pe^rt, then what is the approximate…
question 8 of 10 if f(3) = 191.5 when r = 0.03 for the function f(t)=pe^rt, then what is the approximate value of p? a. 210 b. 78 c. 175 d. 471
Answer
Explanation:
Step1: Substitute values into the function
Given $f(t)=Pe^{rt}$, when $t = 3$, $r=0.03$ and $f(3)=191.5$, we have $191.5 = Pe^{0.03\times3}$, so $191.5 = Pe^{0.09}$.
Step2: Solve for P
We can rewrite the equation as $P=\frac{191.5}{e^{0.09}}$. Since $e^{0.09}\approx1.094174$, then $P=\frac{191.5}{1.094174}\approx175$.
Answer:
C. 175