question 4 of 10 for the function f(t)=pe^rt, if p = 6 and r = 0.06, then what is the value of f(6) to the…

question 4 of 10 for the function f(t)=pe^rt, if p = 6 and r = 0.06, then what is the value of f(6) to the nearest tenth? a. 8.6 b. 219.6 c. 2.2 d. 0.1

question 4 of 10 for the function f(t)=pe^rt, if p = 6 and r = 0.06, then what is the value of f(6) to the nearest tenth? a. 8.6 b. 219.6 c. 2.2 d. 0.1

Answer

Explanation:

Step1: Substitute values into function

Given $f(t)=Pe^{rt}$, substitute $P = 6$, $r=0.06$ and $t = 6$. So $f(6)=6e^{0.06\times6}$.

Step2: Calculate exponent value

First, calculate $0.06\times6 = 0.36$. Then $f(6)=6e^{0.36}$.

Step3: Find the value of $e^{0.36}$

Using a calculator, $e^{0.36}\approx1.433329$.

Step4: Calculate $f(6)$

Multiply 6 by $1.433329$, $f(6)=6\times1.433329 = 8.599974$.

Step5: Round to nearest tenth

Rounding $8.599974$ to the nearest tenth gives $8.6$.

Answer:

A. 8.6