question 12 of 20 \n___\frac{pi}{3}sin\frac{pi}{6}=\frac{1}{2}(sin\frac{pi}{2}-sin\frac{pi}{6})\nanswer here

question 12 of 20 \n___\frac{pi}{3}sin\frac{pi}{6}=\frac{1}{2}(sin\frac{pi}{2}-sin\frac{pi}{6})\nanswer here

question 12 of 20 \n___\frac{pi}{3}sin\frac{pi}{6}=\frac{1}{2}(sin\frac{pi}{2}-sin\frac{pi}{6})\nanswer here

Answer

Answer:

False

Explanation:

Step1: Calculate left - hand side

$\frac{\pi}{3}\sin\frac{\pi}{6}=\frac{\pi}{3}\times\frac{1}{2}=\frac{\pi}{6}$

Step2: Calculate right - hand side

$\frac{1}{2}(\sin\frac{\pi}{2}-\sin\frac{\pi}{6})=\frac{1}{2}(1 - \frac{1}{2})=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}$ Since $\frac{\pi}{6}\neq\frac{1}{4}$, the statement is false.