question 9 of 12 < > the value of a mutual fund increases at a rate of r = 350e^0.04t dollars per year…

question 9 of 12 < > the value of a mutual fund increases at a rate of r = 350e^0.04t dollars per year, where t is years since 2010. (a) using t = 0, 2, 4, 6, 8, 10, make a table of values for r. round your answers to two decimal places. t r(t) 0 i 2 i 4 i 6 i 8 i 10 i

question 9 of 12 < > the value of a mutual fund increases at a rate of r = 350e^0.04t dollars per year, where t is years since 2010. (a) using t = 0, 2, 4, 6, 8, 10, make a table of values for r. round your answers to two decimal places. t r(t) 0 i 2 i 4 i 6 i 8 i 10 i

Answer

Explanation:

Step1: Substitute t = 0

Substitute $t = 0$ into $R = 350e^{0.04t}$. Since $e^{0}=1$, then $R(0)=350e^{0.04\times0}=350\times1 = 350.00$.

Step2: Substitute t = 2

Substitute $t = 2$ into $R = 350e^{0.04t}$. Then $R(2)=350e^{0.04\times2}=350e^{0.08}\approx350\times1.0833=379.16$.

Step3: Substitute t = 4

Substitute $t = 4$ into $R = 350e^{0.04t}$. Then $R(4)=350e^{0.04\times4}=350e^{0.16}\approx350\times1.1735=410.73$.

Step4: Substitute t = 6

Substitute $t = 6$ into $R = 350e^{0.04t}$. Then $R(6)=350e^{0.04\times6}=350e^{0.24}\approx350\times1.2712=444.92$.

Step5: Substitute t = 8

Substitute $t = 8$ into $R = 350e^{0.04t}$. Then $R(8)=350e^{0.04\times8}=350e^{0.32}\approx350\times1.3771=481.99$.

Step6: Substitute t = 10

Substitute $t = 10$ into $R = 350e^{0.04t}$. Then $R(10)=350e^{0.04\times10}=350e^{0.4}\approx350\times1.4918=522.13$.

Answer:

t R(t)
0 350.00
2 379.16
4 410.73
6 444.92
8 481.99
10 522.13