question 14\n23x + 56y = 0\n$\frac{dy}{dx}=?$

question 14\n23x + 56y = 0\n$\frac{dy}{dx}=?$
Answer
Answer:
$-\frac{23}{56}$
Explanation:
Step1: Differentiate both sides
Differentiate $23x + 56y=0$ with respect to $x$. The derivative of $23x$ with respect to $x$ is $23$, and using the chain - rule, the derivative of $56y$ with respect to $x$ is $56\frac{dy}{dx}$. So we have $23 + 56\frac{dy}{dx}=0$.
Step2: Solve for $\frac{dy}{dx}$
Subtract 23 from both sides: $56\frac{dy}{dx}=-23$. Then divide both sides by 56 to get $\frac{dy}{dx}=-\frac{23}{56}$.