question 14 (1 point)\nwhat is the measure of da, if \\( \\sec a = \\sqrt { 2 } \\) and da is located in the…

Explanation:

Step1: Recall the secant - cosine relationship

We know that (\sec A=\frac{1}{\cos A}). Given (\sec A = \sqrt{2}), then (\cos A=\frac{1}{\sqrt{2}}).

Step2: Find the angle (A) using the inverse - cosine function

If (\cos A=\frac{1}{\sqrt{2}}), then (A = \cos^{-1}(\frac{1}{\sqrt{2}})). We know that (\cos45^{\circ}=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}) and the range of the inverse - cosine function (y = \cos^{-1}(x)) is ([0,\pi]) (or ([0^{\circ},180^{\circ}])). Since the angle (A) is in the first quadrant ((0^{\circ}<A < 90^{\circ})), and (\cos^{-1}(\frac{1}{\sqrt{2}})=45^{\circ})

Answer:

B. (45^{\circ})