question 2 of 26. $\frac{d}{dx}(5^{x})=$\n$\\frac{5^{x}}{ln 5}$ $(5^{x - 1})x$ $5^{x - 1}$ $5^{x}ln 5$

Explanation:

Step1: Recall exponential - derivative formula

The derivative of $a^x$ with respect to $x$ is $a^x\ln a$, where $a > 0,a\neq1$. Here $a = 5$.

Step2: Apply the formula

For the function $y = 5^x$, its derivative $\frac{d}{dx}(5^x)=5^x\ln 5$.

Answer:

$5^x\ln 5$