question 26 1 pts what is the equation of the midline of the graph of the function: y = 2 cos 5 (x - 5π/6)…

question 26 1 pts what is the equation of the midline of the graph of the function: y = 2 cos 5 (x - 5π/6) - 6 y = 0 y = -6 y = 2 y = 5 question 27 1 pts what is the period of the function: y = 5 sin 3 (x + π/2) + 7 3 2π/3 5 3π/2

question 26 1 pts what is the equation of the midline of the graph of the function: y = 2 cos 5 (x - 5π/6) - 6 y = 0 y = -6 y = 2 y = 5 question 27 1 pts what is the period of the function: y = 5 sin 3 (x + π/2) + 7 3 2π/3 5 3π/2

Answer

Answer:

Question 26:

B. y = -6

Question 27:

B. $\frac{2\pi}{3}$

Explanation:

Question 26:

Step1: Identificar la forma general

La forma general de una función coseno es $y = A\cos(B(x - C))+D$. La ecuación de la línea media es $y = D$.

Step2: Determinar el valor de D

Para la función $y = 2\cos5(x-\frac{5\pi}{6})-6$, $D=-6$. Entonces, la ecuación de la línea media es $y = -6$.

Question 27:

Step1: Recordar la fórmula del período

La fórmula para el período de una función seno $y = A\sin(B(x - C))+D$ es $T=\frac{2\pi}{|B|}$.

Step2: Identificar el valor de B

Para la función $y = 5\sin3(x+\frac{\pi}{2})+7$, $B = 3$.

Step3: Calcular el período

$T=\frac{2\pi}{|3|}=\frac{2\pi}{3}$.