question 9\nevaluate the limit: $lim_{x \to 4}\frac{x^{2}+2x - 4}{x + 1}$.\ndne\n0\n4\n5\n$infty$

question 9\nevaluate the limit: $lim_{x \to 4}\frac{x^{2}+2x - 4}{x + 1}$.\ndne\n0\n4\n5\n$infty$

question 9\nevaluate the limit: $lim_{x \to 4}\frac{x^{2}+2x - 4}{x + 1}$.\ndne\n0\n4\n5\n$infty$

Answer

Explanation:

Step1: Substitute x = 4

Substitute (x = 4) into the function (\frac{x^{2}+2x - 4}{x + 1}). [ \begin{align*} \frac{4^{2}+2\times4-4}{4 + 1}&=\frac{16+8 - 4}{5}\ &=\frac{20}{5} \end{align*} ]

Step2: Simplify the result

Simplify (\frac{20}{5}). (\frac{20}{5}=4)

Answer:

C. 4