question\nevaluate the limit:\n$lim_{x\rightarrow13}\frac{sqrt{x - 12}-10}{x - 3}$

Answer:

$\frac{\sqrt{13 - 12}-10}{13 - 3}=\frac{1 - 10}{10}=-\frac{9}{10}$

Explanation:

Step1: Substitute $x = 13$

$\lim_{x\rightarrow13}\frac{\sqrt{x - 12}-10}{x - 3}=\frac{\sqrt{13 - 12}-10}{13 - 3}$

Step2: Simplify numerator and denominator

$\frac{\sqrt{1}-10}{10}=\frac{1 - 10}{10}$

Step3: Calculate the result

$\frac{1 - 10}{10}=-\frac{9}{10}$