question find ∫₂³(6x² - 4x)dx answer attempt 1 out of 3 submit answer

Answer:

$22$

Explanation:

Step1: Find antiderivative

$\int(6x^{2}-4x)dx = 6\times\frac{x^{3}}{3}-4\times\frac{x^{2}}{2}=2x^{3}-2x^{2}+C$

Step2: Apply fundamental theorem of calculus

$\left[2x^{3}-2x^{2}\right]_2^3=(2\times3^{3}-2\times3^{2})-(2\times2^{3}-2\times2^{2})$

Step3: Calculate the values

$(2\times27 - 2\times9)-(2\times8 - 2\times4)=(54 - 18)-(16 - 8)=36 - 8=22$