question 7\nif ln(1 / e²)=x, what is the value of x?

Explanation:

Step1: Use logarithm property

Recall that $\ln(\frac{1}{a})=-\ln(a)$ and $\ln(e^b) = b$. So, $\ln(\frac{1}{e^2})=-\ln(e^2)$.

Step2: Evaluate $\ln(e^2)$

Since $\ln(e^b)=b$, when $b = 2$, $\ln(e^2)=2$. Then $-\ln(e^2)=- 2$.

Answer:

$-2$