question 2 (1 point)\nwhich pair of angles between 0° and 360° satisfies sin θ = -1/√2?\na) 45° and 135°\nb)…

question 2 (1 point)\nwhich pair of angles between 0° and 360° satisfies sin θ = -1/√2?\na) 45° and 135°\nb) 45° and 0°\nc) -45° and 225°\nd) 225° and 315°

question 2 (1 point)\nwhich pair of angles between 0° and 360° satisfies sin θ = -1/√2?\na) 45° and 135°\nb) 45° and 0°\nc) -45° and 225°\nd) 225° and 315°

Answer

Explanation:

Step1: Recall the unit - circle values

We know that (\sin45^{\circ}=\frac{1}{\sqrt{2}}). The sine function is negative in the third and fourth quadrants.

Step2: Find angles in the third and fourth quadrants

For the third - quadrant angle: (\theta = 180^{\circ}+45^{\circ}=225^{\circ}) For the fourth - quadrant angle: (\theta = 360^{\circ}-45^{\circ}=315^{\circ})

Answer:

D. (225^{\circ}) and (315^{\circ})