question the radius of a circle is decreasing at a constant rate of 3 inches per minute. at the instant when…

question the radius of a circle is decreasing at a constant rate of 3 inches per minute. at the instant when the radius of the circle is 8 inches, what is the rate of change in the area? round your answer to three decimal places.
Answer
Explanation:
Step1: Recall the area formula
The area formula of a circle is $A = \pi r^{2}$, where $A$ is the area and $r$ is the radius.
Step2: Differentiate with respect to time
Differentiate both sides of the equation $A=\pi r^{2}$ with respect to time $t$ using the chain - rule. $\frac{dA}{dt}=2\pi r\frac{dr}{dt}$.
Step3: Identify given values
We are given that $\frac{dr}{dt}=- 3$ inches per minute (negative because the radius is decreasing) and $r = 8$ inches.
Step4: Substitute values
Substitute $r = 8$ and $\frac{dr}{dt}=-3$ into the equation $\frac{dA}{dt}=2\pi r\frac{dr}{dt}$. So, $\frac{dA}{dt}=2\pi\times8\times(-3)$.
Step5: Calculate the result
$\frac{dA}{dt}=-48\pi\approx - 150.796$ square inches per minute.
Answer:
$-150.796$