question a rocket is launched from a tower. the height of the rocket, y in feet, is related to the time…

question a rocket is launched from a tower. the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y = -16x² + 247x + 81

question a rocket is launched from a tower. the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y = -16x² + 247x + 81

Answer

Explanation:

Step1: Identify the coefficients

The quadratic - function is in the form (y = ax^{2}+bx + c), where (a=-16), (b = 247), (c = 81).

Step2: Use the formula for the x - coordinate of the vertex

The x - coordinate of the vertex of a quadratic function (y = ax^{2}+bx + c) is given by (x=-\frac{b}{2a}). Substitute (a=-16) and (b = 247) into the formula: [x=-\frac{247}{2\times(-16)}]

Step3: Calculate the value of x

[x=\frac{247}{32}=7.71875\approx7.72]

Answer:

(7.72)