question a rocket is launched from a tower. the height of the rocket, y in feet, is related to the time…

question a rocket is launched from a tower. the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y = -16x² + 135x + 65 answer attempt 1 out of 2 submit answer

question a rocket is launched from a tower. the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second. y = -16x² + 135x + 65 answer attempt 1 out of 2 submit answer

Answer

Explanation:

Step1: Identify the coefficients

The given quadratic - function is (y = - 16x^{2}+135x + 65), where (a=-16), (b = 135), and (c = 65). For a quadratic function (y = ax^{2}+bx + c), the x - coordinate of the vertex (which gives the time of maximum height for the rocket) is given by the formula (x=-\frac{b}{2a}).

Step2: Substitute the values

Substitute (a=-16) and (b = 135) into the formula (x=-\frac{b}{2a}). [x=-\frac{135}{2\times(-16)}=\frac{135}{32}]

Step3: Calculate the value

(\frac{135}{32}=4.21875\approx4.22)

Answer:

4.22