question 1 of 9, step 2 of 2 correct consider the following function p(x) = 1/(x - 2)^2 + 1 step 2 of 2…

question 1 of 9, step 2 of 2 correct consider the following function p(x) = 1/(x - 2)^2 + 1 step 2 of 2: identify the shape of the more basic function found in step 1.

question 1 of 9, step 2 of 2 correct consider the following function p(x) = 1/(x - 2)^2 + 1 step 2 of 2: identify the shape of the more basic function found in step 1.

Answer

Explanation:

Step1: Identify the basic - function

The basic function of $p(x)=\frac{1}{(x - 2)^2}+1$ is $y=\frac{1}{x^2}$.

Step2: Recall the shape of $y = \frac{1}{x^2}$

The function $y=\frac{1}{x^2}$ is a reciprocal - squared function. Its graph is a U - shaped curve called a hyperbola - like shape (specifically, a type of rational function graph). It has a vertical asymptote at $x = 0$ and is symmetric about the y - axis.

Answer:

Hyperbola - like shape (reciprocal - squared function shape)