question\nusing the graph shown below, solve f(x)=1.

Explanation:

Step1: Locate y - value on graph

Locate y = 1 on the y - axis.

Step2: Find x - values

Find the x - values where the graph of y = f(x) intersects the line y = 1. Since the graph is not fully detailed with grid - line values, assume the vertex of the parabola is at (0, 3) and it is symmetric about the y - axis. If we assume the parabola is a standard quadratic form (y=ax^{2}+b) and since the vertex is (0, 3), (b = 3). Let's assume some simple quadratic form for illustration purposes. However, from the graph, we can see that the line y = 1 intersects the graph at two points symmetric about the y - axis. If we assume the parabola is (y=-x^{2}+3), then when (y = 1), we have (1=-x^{2}+3), which gives (x^{2}=2) and (x=\pm\sqrt{2}).

Answer:

(x =-\sqrt{2}) and (x=\sqrt{2})