question write the equation of the trigonometric function shown in the graph.

question write the equation of the trigonometric function shown in the graph.

question write the equation of the trigonometric function shown in the graph.

Answer

Explanation:

Step1: Determine the general form

The general form of a sinusoidal function is $y = A\sin(Bx - C)+D$ or $y = A\cos(Bx - C)+D$. The graph passes through the origin, so we can use the sine - form $y = A\sin(Bx - C)+D$.

Step2: Find the amplitude $A$

The amplitude $A$ is half of the vertical distance between the maximum and minimum values. The maximum value is $y = 2$ and the minimum value is $y = 0$. So, $A=\frac{2 - 0}{2}=1$.

Step3: Find the period $T$ and $B$

The period $T$ is the horizontal distance between two consecutive maxima or minima. Here, $T = 180^{\circ}=\pi$ (in radians). Since $T=\frac{2\pi}{B}$, and $T = \pi$, then $B = 2$.

Step4: Find the phase - shift $C$ and vertical shift $D$

The graph passes through the origin $(0,1)$. Substituting $x = 0$, $y = 1$, $A = 1$, and $B = 2$ into $y=A\sin(Bx - C)+D$, we get $1 = 1\times\sin(0 - C)+D$. The mid - line of the graph is $y = 1$, so $D = 1$. And since the graph starts at the mid - line value when $x = 0$, $C = 0$.

Answer:

$y=\sin(2x)+1$