question 6 could you use lhopitals rule to solve the following question in its current form: lim_{x→0^{+}}…

question 6 could you use lhopitals rule to solve the following question in its current form: lim_{x→0^{+}} \frac{ln(x + 1)}{e^{x}}? false true

question 6 could you use lhopitals rule to solve the following question in its current form: lim_{x→0^{+}} \frac{ln(x + 1)}{e^{x}}? false true

Answer

Explanation:

Step1: Recall L'Hopital's rule condition

L'Hopital's rule applies when we have an indeterminate form $\frac{0}{0}$ or $\frac{\infty}{\infty}$.

Step2: Evaluate the limit of numerator and denominator as $x\rightarrow0^{+}$

$\lim_{x\rightarrow0^{+}}\ln(x + 1)=\ln(0 + 1)=0$ and $\lim_{x\rightarrow0^{+}}e^{x}=e^{0}=1$. The form is $\frac{0}{1}$, not an indeterminate form for L'Hopital's rule.

Answer:

A. false