what is the range of f(x) = 3^x + 9?\no {y|y<9}\no {y|y>9}\no {y|y>3}\no {y|y<3}

Explanation:

Step1: Analyze the exponential function

The exponential function $y = 3^{x}$ has a range of $(0,+\infty)$, that is $3^{x}>0$ for all real - valued $x$.

Step2: Find the range of $f(x)$

Let $y = f(x)=3^{x}+9$. Since $3^{x}>0$, then $y=3^{x}+9>0 + 9$. So $y>9$.

Answer:

{y|y > 9}