what is the range of the function y = 2e^x - 1?\nall real numbers less than -1\nall real numbers greater…

Explanation:

Step1: Analyze the exponential - function property

The exponential function $e^{x}$ has a range of $(0,+\infty)$, that is $e^{x}>0$ for all real - valued $x$.

Step2: Multiply by 2

Multiply both sides of the inequality $e^{x}>0$ by 2. We get $2e^{x}>0\times2$, so $2e^{x}>0$.

Step3: Subtract 1

Subtract 1 from both sides of the inequality $2e^{x}>0$. We have $2e^{x}-1>0 - 1$, so $2e^{x}-1>-1$.

Answer:

all real numbers greater than -1