what is the range of the function y = 2sin x?\na. 2π\nb. -2,2\nc. all real numbers\nd. π
what is the range of the function y = 2sin x?\na. 2π\nb. -2,2\nc. all real numbers\nd. π
Answer
Explanation:
Step1: Recall range of sin x
The range of the basic sine - function (y = \sin x) is ([- 1,1]), that is (-1\leqslant\sin x\leqslant1).
Step2: Multiply by 2
Multiply each part of the inequality (-1\leqslant\sin x\leqslant1) by 2. We get (2\times(-1)\leqslant2\sin x\leqslant2\times1), which simplifies to (-2\leqslant2\sin x\leqslant2).
Answer:
B. ([-2,2])