what is the rate of change of the function shown on the graph? round to the nearest tenth.\n2.00\n2.50\n5.25\…

what is the rate of change of the function shown on the graph? round to the nearest tenth.\n2.00\n2.50\n5.25\n10.50
Answer
Explanation:
Step1: Recall rate - of - change formula
The rate of change (slope) between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let's use the points $(1,5)$ and $(2,12.5)$.
Step2: Substitute values into formula
$x_1 = 1,y_1 = 5,x_2=2,y_2 = 12.5$. Then $m=\frac{12.5 - 5}{2 - 1}$.
Step3: Calculate the value
$m=\frac{7.5}{1}=7.5$. But if we use the points $(0,2)$ and $(1,5)$: $m=\frac{5 - 2}{1 - 0}=\frac{3}{1}=3$. Using the points $( - 1,0.8)$ and $(0,2)$: $m=\frac{2 - 0.8}{0-( - 1)}=\frac{1.2}{1}=1.2$. Averaging these rates of change over small intervals or considering the overall trend, if we use the points $(1,5)$ and $(2,12.5)$: $m=\frac{12.5 - 5}{2 - 1}=7.5$. Rounding to the nearest tenth, we consider the best - fit for the non - linear function's overall rate of change. If we assume a linear approximation over the interval from $(1,5)$ to $(2,12.5)$: $m=\frac{12.5 - 5}{2 - 1}=7.5\approx 7.5$. But if we consider the general trend and use two well - spaced points like $(0,2)$ and $(2,12.5)$: $m=\frac{12.5 - 2}{2 - 0}=\frac{10.5}{2}=5.25$.
Answer:
5.25