what is the rate of change for michael redds points per game between seasons 1 and 4?\nfind the average rate…

what is the rate of change for michael redds points per game between seasons 1 and 4?\nfind the average rate of change for the function, shown above, over the interval -3 ≤ x ≤ -1.
Answer
Explanation:
Step1: Recall average rate - of - change formula
The average rate of change of a function $y = f(x)$ over the interval $[a,b]$ is given by $\frac{f(b)-f(a)}{b - a}$.
Step2: For Michael Redd's points per game
Let's assume the number of seasons is on the $x$ - axis and points per game (PPG) is on the $y$ - axis. Suppose the starting season is $x_1$ and the ending season is $x_2$, and the corresponding PPG values are $y_1$ and $y_2$. However, since no specific values for the seasons and PPG are given in a numerical form in the description (only a graph), we can't calculate a numerical value. But the formula for the rate of change of Michael Redd's PPG between seasons $x_1$ and $x_2$ is $\frac{y_2 - y_1}{x_2 - x_1}$.
Step3: For the given function
The interval is $-3\leq x\leq - 1$. Let $a=-3$ and $b = - 1$. We need to find $f(-3)$ and $f(-1)$ from the graph. Suppose $f(-3)=y_1$ and $f(-1)=y_2$. Then the average rate of change is $\frac{f(-1)-f(-3)}{-1-(-3)}=\frac{f(-1)-f(-3)}{2}$.
Answer:
For Michael Redd's PPG: $\frac{y_2 - y_1}{x_2 - x_1}$ (where $x_1,x_2$ are seasons and $y_1,y_2$ are corresponding PPG values). For the function over the interval $-3\leq x\leq - 1$: $\frac{f(-1)-f(-3)}{2}$ (where $f(-3)$ and $f(-1)$ are the function values at $x=-3$ and $x = - 1$ respectively).