where is the removable discontinuity of f(x) located?\n○ x = -5\n○ x = 0\n○ x = -2\n○ x = 5
where is the removable discontinuity of f(x) located?\n○ x = -5\n○ x = 0\n○ x = -2\n○ x = 5
Answer
Explanation:
Step1: Recall removable - discontinuity concept
A removable discontinuity occurs when there is a hole in the graph of the function. It happens when a factor in the numerator and denominator of a rational - function cancels out. Visually, it is a single point where the function is not defined but can be made continuous by re - defining the function at that point.
Step2: Analyze the graph
Looking at the graph, we can see that there is a hole in the graph at (x = - 2). At (x=-5), there is a vertical asymptote (the function shoots to infinity), at (x = 0) the function is continuous, and at (x = 5) the function is also continuous.
Answer:
(x=-2)