review the graph. which function is represented in the graph? o y = tanx o y = cosx o y = tan^(-1)x o y =…

Explanation:

Step1: Recall properties of trig - functions

The function (y = \tan x) has vertical asymptotes at (x=\frac{\pi}{2}+n\pi,n\in\mathbb{Z}), and its range is ((-\infty,\infty)). The function (y=\cos x) has a range of ([- 1,1]) and is periodic with period (2\pi). The function (y = \tan^{-1}x) has a range of ((-\frac{\pi}{2},\frac{\pi}{2})) and is an increasing function with horizontal asymptotes (y =-\frac{\pi}{2}) and (y=\frac{\pi}{2}). The function (y=\cos^{-1}x) has a range of ([0,\pi]) and is a decreasing function.

Step2: Analyze the given graph

The given graph has a range of ([0,\pi]) and is a decreasing function of (x) for (x\in[- 1,1]).

Answer:

(y = \cos^{-1}x)