review the graph of function f(x). which statement identifies and explains lim f(x) as x→0? the limit lim…

review the graph of function f(x). which statement identifies and explains lim f(x) as x→0? the limit lim f(x) as x→0 = -2 because the value of the function at x = 0 is -2. the limit lim f(x) as x→0 does not exist because there is an open circle at (0, 4). the limit lim f(x) as x→0 = 4 because both the left - hand and right - hand limits equal 4. the limit lim f(x) as x→0 does not exist because there is oscillating behavior around x = 0.

review the graph of function f(x). which statement identifies and explains lim f(x) as x→0? the limit lim f(x) as x→0 = -2 because the value of the function at x = 0 is -2. the limit lim f(x) as x→0 does not exist because there is an open circle at (0, 4). the limit lim f(x) as x→0 = 4 because both the left - hand and right - hand limits equal 4. the limit lim f(x) as x→0 does not exist because there is oscillating behavior around x = 0.

Answer

Explanation:

Step1: Recall limit definition

The limit as $x\to a$ exists if left - hand limit and right - hand limit are equal.

Step2: Analyze graph

Around $x = 0$, the function has oscillating behavior. Limit requires a single value as $x$ approaches a point.

Answer:

The limit $\lim_{x\to0}f(x)$ does not exist because there is oscillating behavior around $x = 0$.