review the incomplete derivation of the cosine sum identity. which expressions for step 3 and step 5…

review the incomplete derivation of the cosine sum identity. which expressions for step 3 and step 5 complete the derivation? step 1: \\( cos(x + y) \\) step 2: \\( sinleft( \frac{pi}{2}(x + y) \right) \\) step 3: step 4: \\( sinleft( \frac{pi}{2}-x \right)cos(y)-cosleft( \frac{pi}{2}-x \right)sin(y) \\) step 5: step 3: \\( sinleft( (\frac{pi}{2}-x)+y \right) \\) step 5: \\( cos(x)cos(y)+sin(x)sin(y) \\) step 3: \\( sinleft( (\frac{pi}{2}-x)+y \right) \\) step 5: \\( cos(x)cos(y)-sin(x)sin(y) \\) step 3: \\( sinleft( (\frac{pi}{2}-x)-y \right) \\) step 5: \\( cos(x)cos(y)+sin(x)sin(y) \\) step 3: \\( sinleft( (\frac{pi}{2}-x)-y \right) \\) step 5: \\( cos(x)cos(y)-sin(x)sin(y) \\)

review the incomplete derivation of the cosine sum identity. which expressions for step 3 and step 5 complete the derivation? step 1: \\( cos(x + y) \\) step 2: \\( sinleft( \frac{pi}{2}(x + y) \right) \\) step 3: step 4: \\( sinleft( \frac{pi}{2}-x \right)cos(y)-cosleft( \frac{pi}{2}-x \right)sin(y) \\) step 5: step 3: \\( sinleft( (\frac{pi}{2}-x)+y \right) \\) step 5: \\( cos(x)cos(y)+sin(x)sin(y) \\) step 3: \\( sinleft( (\frac{pi}{2}-x)+y \right) \\) step 5: \\( cos(x)cos(y)-sin(x)sin(y) \\) step 3: \\( sinleft( (\frac{pi}{2}-x)-y \right) \\) step 5: \\( cos(x)cos(y)+sin(x)sin(y) \\) step 3: \\( sinleft( (\frac{pi}{2}-x)-y \right) \\) step 5: \\( cos(x)cos(y)-sin(x)sin(y) \\)

Answer

Explanation:

Step1: Use the co - function identity

We know that (\cos(A)=\sin\left(\frac{\pi}{2}-A\right)). So, if (A = x + y), then (\cos(x + y)=\sin\left(\frac{\pi}{2}-(x + y)\right)=\sin\left(\left(\frac{\pi}{2}-x\right)-y\right))

Step2: Use the sine difference formula

The sine difference formula is (\sin(A - B)=\sin(A)\cos(B)-\cos(A)\sin(B)). Here (A=\frac{\pi}{2}-x) and (B = y), so (\sin\left(\left(\frac{\pi}{2}-x\right)-y\right)=\sin\left(\frac{\pi}{2}-x\right)\cos(y)-\cos\left(\frac{\pi}{2}-x\right)\sin(y))

Step3: Use co - function identities again

We know that (\sin\left(\frac{\pi}{2}-x\right)=\cos(x)) and (\cos\left(\frac{\pi}{2}-x\right)=\sin(x)) [ \begin{align*} \sin\left(\frac{\pi}{2}-x\right)\cos(y)-\cos\left(\frac{\pi}{2}-x\right)\sin(y)&=\cos(x)\cos(y)-\sin(x)\sin(y) \end{align*} ]

Answer:

Step 3: (\sin\left(\left(\frac{\pi}{2}-x\right)-y\right)), Step 5: (\cos(x)\cos(y)-\sin(x)\sin(y)) (the fourth option)