review the steps in the derivation of the tangent sum identity. the steps are not in order. which list shows…

review the steps in the derivation of the tangent sum identity. the steps are not in order. which list shows the steps in the correct order? i sin(x + y)/cos(x + y) ii (sin(x)cos(y)/cos(x)cos(y) + cos(x)sin(y)/cos(x)cos(y))/(cos(x)cos(y)/cos(x)cos(y) - sin(x)sin(y)/cos(x)cos(y)) iii (tan(x) + tan(y))/(1 - tan(x)tan(y)) o i → ii → iv → iii o i → iv → ii → iii o iii → i → ii → iv o iii → i → iv → ii. mark this and return

review the steps in the derivation of the tangent sum identity. the steps are not in order. which list shows the steps in the correct order? i sin(x + y)/cos(x + y) ii (sin(x)cos(y)/cos(x)cos(y) + cos(x)sin(y)/cos(x)cos(y))/(cos(x)cos(y)/cos(x)cos(y) - sin(x)sin(y)/cos(x)cos(y)) iii (tan(x) + tan(y))/(1 - tan(x)tan(y)) o i → ii → iv → iii o i → iv → ii → iii o iii → i → ii → iv o iii → i → iv → ii. mark this and return

Answer

Explanation:

Step1: Start with tangent definition

We know that $\tan(A + B)=\frac{\sin(A + B)}{\cos(A + B)}$, so we start with step I: $\frac{\sin(x + y)}{\cos(x + y)}$.

Step2: Apply sum - of - angles formulas

Using the sum - of - angles formulas $\sin(x + y)=\sin(x)\cos(y)+\cos(x)\sin(y)$ and $\cos(x + y)=\cos(x)\cos(y)-\sin(x)\sin(y)$, we get $\frac{\sin(x)\cos(y)+\cos(x)\sin(y)}{\cos(x)\cos(y)-\sin(x)\sin(y)}$. Then, dividing each term in the numerator and denominator by $\cos(x)\cos(y)$ gives step II: $\frac{\frac{\sin(x)\cos(y)}{\cos(x)\cos(y)}+\frac{\cos(x)\sin(y)}{\cos(x)\cos(y)}}{\frac{\cos(x)\cos(y)}{\cos(x)\cos(y)}-\frac{\sin(x)\sin(y)}{\cos(x)\cos(y)}}$.

Step3: Simplify using tangent definition

Since $\tan(x)=\frac{\sin(x)}{\cos(x)}$ and $\tan(y)=\frac{\sin(y)}{\cos(y)}$, the expression simplifies to step III: $\frac{\tan(x)+\tan(y)}{1 - \tan(x)\tan(y)}$. And step IV is the intermediate step of dividing by $\cos(x)\cos(y)$. The correct order is I→IV→II→III.

Answer:

I→IV→II→III