score on last try: 0.67 of 1 pts. see details for more. > next question get a similar question you can retry…

score on last try: 0.67 of 1 pts. see details for more. > next question get a similar question you can retry this question below based on the graph above, determine the amplitude, midline, and period of the function amplitude: 5 period: midline: y = - 3 question help: worked example 1 submit question

score on last try: 0.67 of 1 pts. see details for more. > next question get a similar question you can retry this question below based on the graph above, determine the amplitude, midline, and period of the function amplitude: 5 period: midline: y = - 3 question help: worked example 1 submit question

Answer

Explanation:

Step1: Define amplitude

Amplitude is half - the vertical distance between max and min. Max is 2, min is - 8. So, $\frac{2-(-8)}{2}=\frac{10}{2}=5$.

Step2: Define mid - line

Mid - line is average of max and min. $\frac{2 + (-8)}{2}=\frac{2-8}{2}=-3$.

Step3: Define period

Period is the horizontal distance between two consecutive peaks. From the graph, the distance between two consecutive peaks (e.g., from x = - 2 to x = 2) is 4.

Answer:

Period: 4