score on last try: 0 of 1 pts. see details for more. > next question get a similar question you can retry…

score on last try: 0 of 1 pts. see details for more. > next question get a similar question you can retry this question below sketch a graph of the function f(x)=sin(x). -π/4 π/4 π/2 3π/4 π 5π/4 3π/2 7π/4 2π -1 -2 clear all draw: question help: video submit question

score on last try: 0 of 1 pts. see details for more. > next question get a similar question you can retry this question below sketch a graph of the function f(x)=sin(x). -π/4 π/4 π/2 3π/4 π 5π/4 3π/2 7π/4 2π -1 -2 clear all draw: question help: video submit question

Answer

Explanation:

Step1: Identify key - points

The sine function $y = \sin(x)$ has a period of $2\pi$. Its range is $[- 1,1]$. At $x = 0$, $\sin(0)=0$; at $x=\frac{\pi}{2}$, $\sin(\frac{\pi}{2}) = 1$; at $x=\pi$, $\sin(\pi)=0$; at $x=\frac{3\pi}{2}$, $\sin(\frac{3\pi}{2})=-1$; at $x = 2\pi$, $\sin(2\pi)=0$.

Step2: Sketch the curve

Connect the key - points with a smooth curve that oscillates between $y=-1$ and $y = 1$ with a period of $2\pi$. The curve passes through the origin $(0,0)$, reaches a maximum of $y = 1$ at $x=\frac{\pi}{2}$, returns to $y = 0$ at $x=\pi$, reaches a minimum of $y=-1$ at $x=\frac{3\pi}{2}$, and comes back to $y = 0$ at $x = 2\pi$, and then repeats.

Answer:

Sketch a smooth curve passing through $(0,0),(\frac{\pi}{2},1),(\pi,0),(\frac{3\pi}{2},-1),(2\pi,0)$ and repeating with period $2\pi$ and oscillating between $y=-1$ and $y = 1$.