section 03.5: problem 29\n(2 points)\nsuppose (-7,0) is a point on the graph of y = f(x). what is a point…

section 03.5: problem 29\n(2 points)\nsuppose (-7,0) is a point on the graph of y = f(x). what is a point that will be on the graph of y = f(5x)+1?\nhelp (points)\nenter a point as (a,b), including the parentheses.\npreview my answers submit answers show me another\nyou have attempted this problem 0 times.\nyou have unlimited attempts remaining.\nemail instructor

section 03.5: problem 29\n(2 points)\nsuppose (-7,0) is a point on the graph of y = f(x). what is a point that will be on the graph of y = f(5x)+1?\nhelp (points)\nenter a point as (a,b), including the parentheses.\npreview my answers submit answers show me another\nyou have attempted this problem 0 times.\nyou have unlimited attempts remaining.\nemail instructor

Answer

Explanation:

Step1: Analyze the horizontal transformation

For the function (y = f(5x)), if ((x_1,y_1)) is on (y = f(x)), then for (y = f(5x)), we set (5x=x_1). Given (x_1=-7), then (5x=-7), so (x =-\frac{7}{5}).

Step2: Analyze the vertical transformation

For the function (y = f(5x)+1), since (y_1 = f(x_1)=0) (because ((-7,0)) is on (y = f(x))), then (y=f(5x)+1). Substituting (x =-\frac{7}{5}) into (y = f(5x)+1), we get (y=f(-7)+1). Since (f(-7) = 0), then (y=0 + 1=1).

Answer:

(\left(-\frac{7}{5},1\right))