select the correct answer. which function has a phase shift of $\frac{pi}{2}$ to the right?\na. $y =…

select the correct answer. which function has a phase shift of $\frac{pi}{2}$ to the right?\na. $y = 2sin(2x-pi)$\nb. $y = 2sin(\frac{1}{2}x+pi)$\nc. $y = 2sin(x - pi)$\nd. $y = 2sin(x+\frac{pi}{2})$
Answer
Answer:
A. $y = 2\sin(2x-\pi)$
Explanation:
Step1: Recall phase - shift formula
For $y = A\sin(Bx - C)+D$, phase - shift is $\frac{C}{B}$.
Step2: Analyze option A
For $y = 2\sin(2x-\pi)$, $A = 2$, $B = 2$, $C=\pi$. Phase - shift is $\frac{\pi}{2}$ to the right since $\frac{C}{B}=\frac{\pi}{2}$ and the form is $Bx - C$.
Step3: Analyze option B
For $y = 2[Client Connection Error]