this is similar to section 3.4 problem 8: for the function f(x)=2xe^{3x}, determine its critical number(s)…

this is similar to section 3.4 problem 8: for the function f(x)=2xe^{3x}, determine its critical number(s) if exists. use fractions. use \dne\ if the function has no critical number. answer: x= hint: follow example 1. symbolic formatting help
Answer
Explanation:
Step1: Find the derivative
Use the product - rule $(uv)^\prime = u^\prime v+uv^\prime$, where $u = 2x$ and $v = e^{3x}$. The derivative of $u = 2x$ is $u^\prime=2$, and the derivative of $v = e^{3x}$ is $v^\prime = 3e^{3x}$. Then $f^\prime(x)=2e^{3x}+2x\times3e^{3x}=2e^{3x}(1 + 3x)$.
Step2: Set the derivative equal to zero
Set $f^\prime(x)=0$. Since $e^{3x}>0$ for all real - valued $x$, we solve $1 + 3x=0$. $1+3x = 0$ implies $3x=-1$.
Step3: Solve for x
$x=-\frac{1}{3}$.
Answer:
$x =-\frac{1}{3}$