a simple model for travel costs involves the cost of gasoline and the cost of a driver. specifically, assume…

a simple model for travel costs involves the cost of gasoline and the cost of a driver. specifically, assume that ga also, assume that the driver earns $w/hour. complete parts (a) through (g) below. a. a plausible function to describe how gas mileage (in mi/gal) varies with speed is g(v)=v(84 - v)/63. evaluate g(0), g(40), and g(60) and explain why these values are reasonable. g(0)=0.00 mpg (round to two decimal places as needed.) g(40)=27.94 mpg (round to two decimal places as needed.) g(60)=□ mpg (round to two decimal places as needed.)

a simple model for travel costs involves the cost of gasoline and the cost of a driver. specifically, assume that ga also, assume that the driver earns $w/hour. complete parts (a) through (g) below. a. a plausible function to describe how gas mileage (in mi/gal) varies with speed is g(v)=v(84 - v)/63. evaluate g(0), g(40), and g(60) and explain why these values are reasonable. g(0)=0.00 mpg (round to two decimal places as needed.) g(40)=27.94 mpg (round to two decimal places as needed.) g(60)=□ mpg (round to two decimal places as needed.)

Answer

Explanation:

Step1: Substitute v = 60 into the function

Substitute (v = 60) into (g(v)=\frac{v(84 - v)}{63}), we get (g(60)=\frac{60\times(84 - 60)}{63}).

Step2: Calculate the value in the parentheses

First, calculate (84-60 = 24). Then the expression becomes (g(60)=\frac{60\times24}{63}).

Step3: Calculate the product in the numerator

(60\times24=1440), so (g(60)=\frac{1440}{63}).

Step4: Divide to get the result

(\frac{1440}{63}\approx22.86) (rounded to two - decimal places).

Answer:

22.86